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(GMAT 800) If n and a are positive integers, what is the units digit

If n and a are positive integers, what is the units digit of n^(4a+2) – n^(8a)?

(1) n = 3
(2) a is odd

A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked;
B)    Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked;
C)    BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient;
D)    EACH statement ALONE is sufficient to answer the question asked;
E)    Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

BONUS QUESTION: What actually is the units digit (assuming the answer is not E)?


ANSWER BELOW

One important thing to note about exponents is that, by definition, they indicate “repetitive multiplication” – the multiplication of the same number over and over again.  Accordingly, they lend themselves nicely to patterns, as when you perform the  same action over and over again you’ll tend to get similar results.  When you consider statement 1, that n = 3, look at how 3 multiplies to different exponents:

3^1 = 3
3^2 = 9
3^3 = 27
3^4  = 81

And to continue, we’ll just keep multiplying by 3; since the question is only asking about the units digit we’ll use the -> sign to indicate the units digit that the calculation will yield:

3^5 = 81 *3 -> 3
3^6 = 3*3 -> 9
3^7 = 9 * 3 -> 7
3^8 = 7 * 3 -> 1

If you notice, we’re in the midst of a repeating pattern: 3, 9, 7, 1, 3, 9, 7, 1…  The pattern dictates that it will recycle every fourth term, with each exponent-multiple-of-4 giving us a units digit of 1.  So we know that n^8a is going to end in 1.  And if you look closer, n^4a will also end in 1, and that first term from the question is n^(4a+2), meaning that each time we’ll go two iterations past the repeating 1.  Therefore, n^(4a+2) will always end in 9, and n^8a will always end in 1.  Accordingly, statement 1 is sufficient.


Statement 2, however, is not sufficient.  Without knowledge of n itself, we have no information about the base.  If n is 1, the units digit will always be 1; if n is 6, the units digit will always be 6.  Because the base of the exponent will dictate the possible values of the units digit, if we don’t have information about the base we won’t know the units digit, and therefore statement 2 is not sufficient.  Accordingly, the correct answer is A.

Solution: A

BONUS Solution:  Having read the above, you know that our units digits for n^(4a+2) – n^8a will be 9 – 1, so clearly the answer should be 8, right?  This is where the GMAT can become devilishly clever: the answer is not 8, and precious few examinees will answer this question correctly!  If you note the relative values of the exponents, 8a is always going to be bigger than 4a+2 (we are, after all, talking about a as a positive integer).  So we are not subtracting 9 – 1 with the left number being larger; instead, because the number on the right will be the larger number, our subtraction will take the form of 9 – 11, yielding a negative number that ends in 2.  The units digit of this subtraction will be 2, and should serve as a reminder that the GMAT reserves the right to test your level-of-consciousness: beware the often-overlooked number types negative, noninteger, and zero!


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